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Go: fix CLI logout command (#14672)

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### What problem does this PR solve?

```
RAGFlow(user)> logout;
SUCCESS
```

### Type of change

- [x] Bug Fix (non-breaking change which fixes an issue)

Signed-off-by: Jin Hai <haijin.chn@gmail.com>
This commit is contained in:
Jin Hai
2026-05-08 16:47:25 +08:00
committed by GitHub
parent 94f82acd03
commit ce2ec86b5e
2 changed files with 4 additions and 25 deletions
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4
internal/cli/common_command.go
View File

@@ -210,10 +210,10 @@ func (c *RAGFlowClient) Logout() (ResponseIf, error) {
if c.ServerType == "admin" {
path = "/admin/logout"
} else {
path = "/user/logout"
path = "/auth/logout"
}
resp, err := c.HTTPClient.Request("GET", path, "web", nil, nil)
resp, err := c.HTTPClient.Request("POST", path, "web", nil, nil)
if err != nil {
return nil, err
}

25
internal/cli/user_parser.go
View File

@@ -113,27 +113,6 @@ func (p *Parser) parseListCommand() (*Command, error) {
p.nextToken() // consume LIST
switch p.curToken.Type {
case TokenServices:
p.nextToken()
// Semicolon is optional for SHOW TOKEN
if p.curToken.Type == TokenSemicolon {
p.nextToken()
}
return NewCommand("list_services"), nil
case TokenUsers:
p.nextToken()
// Semicolon is optional for SHOW TOKEN
if p.curToken.Type == TokenSemicolon {
p.nextToken()
}
return NewCommand("list_users"), nil
case TokenRoles:
p.nextToken()
// Semicolon is optional for SHOW TOKEN
if p.curToken.Type == TokenSemicolon {
p.nextToken()
}
return NewCommand("list_roles"), nil
case TokenVars:
p.nextToken()
// Semicolon is optional for SHOW TOKEN
@@ -335,9 +314,9 @@ func (p *Parser) parseShowCommand() (*Command, error) {
p.nextToken()
}
return NewCommand("show_current_model"), nil
} else {
return nil, fmt.Errorf("expected USER or MODEL after CURRENT")
}
return nil, fmt.Errorf("expected USER or MODEL after CURRENT")
case TokenUser:
return p.parseShowUser()
case TokenRole: